5sin^2x+3cos^2x=4

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Solution for 5sin^2x+3cos^2x=4 equation: 


Simplifying
5sin2x + 3cos2x = 4

Reorder the terms:
3cos2x + 5in2sx = 4

Solving
3cos2x + 5in2sx = 4

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5in2sx' to each side of the equation.
3cos2x + 5in2sx + -5in2sx = 4 + -5in2sx

Combine like terms: 5in2sx + -5in2sx = 0
3cos2x + 0 = 4 + -5in2sx
3cos2x = 4 + -5in2sx

Divide each side by '3os2x'.
c = 1.333333333o-1s-2x-1 + -1.666666667in2o-1s-1

Simplifying
c = 1.333333333o-1s-2x-1 + -1.666666667in2o-1s-1

Reorder the terms:
c = -1.666666667in2o-1s-1 + 1.333333333o-1s-2x-1

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